给你单链表的头节点

head

,请你反转链表,并返回反转后的链表。

示例 1:

https://assets.leetcode.com/uploads/2021/02/19/rev1ex1.jpg

输入:head = [1,2,3,4,5]
输出:[5,4,3,2,1]

示例 2:

https://assets.leetcode.com/uploads/2021/02/19/rev1ex2.jpg

输入:head = [1,2]
输出:[2,1]

示例 3:

输入:head = []
输出:[]

提示:

/**
 * Definition for singly-linked list.
 * public class ListNode {
 *     int val;
 *     ListNode next;
 *     ListNode() {}
 *     ListNode(int val) { this.val = val; }
 *     ListNode(int val, ListNode next) { this.val = val; this.next = next; }
 * }
 */
class Solution {
    public ListNode reverseList(ListNode head) {
        ListNode middleNode = null;
        ListNode preNode = head;
    
        while ( preNode != null ){
            ListNode newNode = new ListNode(preNode.val );
            newNode.next=middleNode;
            middleNode = newNode;
            preNode = preNode.next;
        }
        return middleNode;
    }
}