编写一个函数，其作用是将输入的字符串反转过来。输入字符串以字符数组 s 的形式给出。

不要给另外的数组分配额外的空间，你必须**原地修改输入数组**、使用 O(1) 的额外空间解决这一问题。

示例 1：

输入：s = ["h","e","l","l","o"]
输出：["o","l","l","e","h"]

示例 2：

输入：s = ["H","a","n","n","a","h"]
输出：["h","a","n","n","a","H"]

提示：

• 1 <= s.length <= 105
• s[i] 都是 ASCII 码表中的可打印字符

class Solution {
   void reverseString(char[] s) {
    // 一左一右两个指针相向而行
    int left = 0, right = s.length - 1;
    while (left < right) {
        // 交换 s[left] 和 s[right]
        char temp = s[left];
        s[left] = s[right];
        s[right] = temp;
        left++;
        right--;
    }
}
}